(3x-4x^2)/(x^2-20)

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Solution for (3x-4x^2)/(x^2-20) equation: 


D( x )

x^2-20 = 0

x^2-20 = 0

x^2-20 = 0

1*x^2 = 20 // : 1

x^2 = 20

x^2 = 20 // ^ 1/2

abs(x) = 2*5^(1/2)

x = 2*5^(1/2) or x = -(2*5^(1/2))

x in (-oo:-(2*5^(1/2))) U (-(2*5^(1/2)):2*5^(1/2)) U (2*5^(1/2):+oo)

(3*x-(4*x^2))/(x^2-20) = 0

(3*x-4*x^2)/(x^2-20) = 0

3*x-4*x^2 = 0

x*(3-4*x) = 0

3-4*x = 0 // - 3

-4*x = -3 // : -4

x = -3/(-4)

x = 3/4

x*(x-3/4) = 0

(x*(x-3/4))/(x^2-20) = 0

( x-3/4 )

x-3/4 = 0 // + 3/4

x = 3/4

( x )

x = 0

x in { 3/4, 0 }

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